(x^2-5x-6)/(5x^2-25x-30)

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Solution for (x^2-5x-6)/(5x^2-25x-30) equation:


D( x )

5*x^2-(25*x)-30 = 0

5*x^2-(25*x)-30 = 0

5*x^2-(25*x)-30 = 0

5*x^2-25*x-30 = 0

5*x^2-25*x-30 = 0

DELTA = (-25)^2-(-30*4*5)

DELTA = 1225

DELTA > 0

x = (1225^(1/2)+25)/(2*5) or x = (25-1225^(1/2))/(2*5)

x = 6 or x = -1

x in (-oo:-1) U (-1:6) U (6:+oo)

(x^2-(5*x)-6)/(5*x^2-(25*x)-30) = 0

(x^2-5*x-6)/(5*x^2-25*x-30) = 0

x^2-5*x-6 = 0

x^2-5*x-6 = 0

DELTA = (-5)^2-(-6*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+5)/(1*2) or x = (5-49^(1/2))/(1*2)

x = 6 or x = -1

(x+1)*(x-6) = 0

5*x^2-25*x-30 = 0

5*(x^2-5*x-6) = 0

x^2-5*x-6 = 0

DELTA = (-5)^2-(-6*1*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)+5)/(1*2) or x = (5-49^(1/2))/(1*2)

x = 6 or x = -1

5*(x+1)*(x-6) = 0

((x+1)*(x-6))/(5*(x+1)*(x-6)) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-6 )

x-6 = 0 // + 6

x = 6

x in { -1}

x in { 6}

x belongs to the empty set

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